JEE Main Chemistry question

CH₃COOH --Br₂/P--> Y --(i) KCN (ii) H₃O⁺--> X. Here X is

(A)Glycollic acid
(B)α-hydroxy propionic acid
(C)Succinic acid
(D)Malonic acidCorrect

Answer: (D)

Solution

Hell–Volhard–Zelinsky bromination (Br₂/P/red P) of acetic acid replaces an α-hydrogen with Br, giving bromoacetic acid, BrCH₂COOH (Y). Substitution of Br by CN (KCN) gives the nitrile

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-149214