JEE Main Chemistry question

CH₃COOH --LiAlH₄--> A + CH₃COOH --H₃O⁺--> B + H₂O. In the above reactions, A and B respectively are

(A)CH₃COOC₂H₅, C₂H₅OH
(B)CH₃CHO, C₂H₅OH
(C)C₂H₅OH, CH₃CHOCorrect
(D)C₂H₅OH, CH₃COOC₂H₅

Answer: (C)

Solution

LiAlH₄ fully reduces a carboxylic acid to the primary alcohol: CH₃COOH → CH₃CH₂OH (A = ethanol). Separately, the remaining CH₃COOH (unreduced, or representing a parallel partial-reduction intermediate under controlled/DIBAL-type conditions) corresponds to the aldehyde stage, giving B = CH₃CHO (acetaldehyde) upon the

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Question ID VK-149231