JEE Main Chemistry question

Identify the compound Z in this reaction sequence: CH₃CH₂COOH --NH₃--> X --Br₂+KOH--> Y --HNO₂--> Z.

(A)CH₃OH
(B)CH₃CH₂NH₂
(C)CH₃CH₂OHCorrect
(D)CH₃CH₂CH₂OH

Answer: (C)

Solution

Propanoic acid with ammonia gives the ammonium salt, which on heating gives the amide, propanamide, CH₃CH₂CONH₂ (X). Hofmann bromamide degradation (Br₂/KOH) of this amide removes one carbon (as CO₂, via isocyanate/carbamate intermediates)

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Question ID VK-149246