JEE Main Chemistry question

RCH₂COOH --Br₂/P--> X --Excess NH₃--> Y. The major amounts of X and Y are

(A)RCHBrCONH₂; RCH(NH₂)COOH
(B)RCHBrCOOH; RCH(NH₂)COOHCorrect
(C)RCOBr; RCH₂COONH₄
(D)RCHBrCOOH; RCH₂CONH₂

Answer: (B)

Solution

HVZ bromination (Br₂/red P) replaces the α-hydrogen of the acid to give the α-bromoacid, RCHBrCOOH (X). Excess ammonia then displaces the α-bromide via nucleophilic substitution (SN2,

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Question ID VK-149264