JEE Main Chemistry question

CH₃COOCH₃ + excess PhMgBr → product --H⁺--> X. The product X is

(A)2-phenyl-2-propanol-type structure, i.e. 1,1-diphenylethanolCorrect
(B)1,1-diphenylethanol, alternate drawing
(C)Methyl phenyl ethanol
(D)Methyl phenyl ketone

Answer: (A)

Solution

With excess PhMgBr, methyl acetate first loses methoxide to give the ketone acetophenone (in situ), which then reacts with a second equivalent of PhMgBr;

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Question ID VK-149304