JEE Main Chemistry question

Acetyl bromide reacts with excess of CH₃MgI followed by treatment with a saturated solution of NH₄Cl gives

(A)Acetone
(B)Acetamide
(C)2-methyl-2-propanolCorrect
(D)Acetyl iodide

Answer: (C)

Solution

With excess Grignard reagent, the acid bromide first forms a ketone (acetone, by substitution of Br by one CH₃ equivalent) which then undergoes a second

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Question ID VK-149322