JEE Main Chemistry question

The correct formula of the product of reaction between φCHO and propanoic anhydride in presence of sodium propionate is

(A)φ–CH=CHCH₂COOH
(B)φCH=CH–CH₂COOC₂H₅
(C)φ–CH=C(CH₃)–COOHCorrect
(D)φ–CH=C(CH₃)–COOC₂H₅

Answer: (C)

Solution

This is a Perkin-type condensation using propanoic anhydride (instead of acetic anhydride) with sodium propionate as base: the α-carbon of the anhydride (which bears a methyl substituent, since it is propanoate-derived) attacks the aromatic aldehyde, and after

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Question ID VK-149378