JEE Main Chemistry question

Which of the following compounds neither forms semicarbazone nor oxime?

(A)H–CO–H (formaldehyde)
(B)CH₃–CO–NH–CH₃ (an N-methylacetamide-type amide)Correct
(C)CH₃–CO–CH₂Cl
(D)CH₃–CH(CH₃)–CHO

Answer: (B)

Solution

Semicarbazones and oximes form by nucleophilic addition–elimination specifically at an aldehyde or ketone carbonyl. An amide carbonyl (here, N-methylacetamide-type structure) is far less electrophilic (the nitrogen lone pair strongly

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Question ID VK-149429