JEE Main Chemistry question

A bicyclic lactone-fused aromatic diester --(i) O₃ (ii) Zn, HCO₃H--> (A). Write the product of the following reaction.

(A)A ring-opened bis-acid/lactone product retaining the aromatic ring and both carbonyl-bearing side chainsCorrect
(B)A fully reduced open-chain diol
(C)A simple mono-acid, loss of one carbonyl fragment
(D)An unreacted starting material

Answer: (A)

Solution

Ozonolysis selectively cleaves the one remaining non-aromatic carbon–carbon double bond in this fused polycyclic substrate (the aromatic ring itself is untouched by ozonolysis under controlled conditions), opening that ring to reveal a pair of new carbonyl-bearing arms while the aromatic core and the pre-existing

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Question ID VK-149438