JEE Main Chemistry question
Match each transformation in Column-I with the reaction name in Column-II, and select the correct code:
| Column-I | Column-II | |---|---| | (A) A cyclic ketone + CF₃COOOH → a lactone | (p) Schmidt | | (B) RCOOH → RCH₂COOH | (q) Baeyer–Villiger | | (C) RCOOH --N₃H/H₂O--> RNH₂ | (r) Arndt–Eistert |
Answer: (A)
Solution
(A) Oxidation of a ketone with a peracid, inserting an oxygen atom next to the carbonyl to give a lactone/ester, is the Baeyer–Villiger oxidation → A–q. (B) Homologation of a carboxylic acid to its next higher one-carbon homologue (via the
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