JEE Main Chemistry question
0.14 g of an acid required 12.5 mL of 0.1 N NaOH for complete neutralization. The equivalent weight of the acid is:
Answer: (D)
Solution
Equivalents of NaOH = N × V(L) = 0.1 × 0.0125 = 0.00125 eq = equivalents of acid. Equivalent weight = mass/equivalents = 0.14/0.00125 = 112.