JEE Main Chemistry question
15 mL of a gaseous hydrocarbon required 45 mL of oxygen for complete combustion. 30 mL of CO₂ is formed. The formula of the hydrocarbon is:
Answer: (B)
Solution
From CO₂ formed: 15x = 30 ⟹ x = 2 carbons. From O₂ used: 15(x + y/4) = 45 ⟹ x + y/4 = 3 ⟹ y/4 = 1 ⟹ y = 4. Formula: C₂H₄.