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JEE Main Chemistry question

ChemistrySome Basic Concepts of ChemistryJEE Main

500 mL of a hydrocarbon gas burnt in excess oxygen yielded 2500 mL of CO₂ and 3.0 litre of water vapour (all volumes measured at the same temperature and pressure). The formula of the hydrocarbon is:

Answer: (C)

Solution

From CO₂: 500x = 2500 ⟹ x = 5. From H₂O: 500(y/2) = 3000 ⟹ y/2 = 6 ⟹ y = 12. Formula: C₅H₁₂.

Question ID VK-149652