JEE Main Chemistry question

Ethyl propanoate (CH₃CH₂COOC₂H₅) (CH₃MgBr, excess)→ P. The product P will be:

(A)2-Methylbutan-2-ol, (CH₃)₂C(OH)(CH₂CH₃)Correct
(B)tert-Butanol, (CH₃)₃COH
(C)3-Methylpentan-3-ol
(D)2-Methylpentan-2-ol

Answer: (A)

Solution

An ester reacts with two equivalents of Grignard reagent (the first displaces ethoxide to give the ketone in situ, the second adds to it); ethyl propanoate with excess

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Question ID VK-150052