JEE Main Chemistry question
Acetophenone →(4[H], Zn(Hg)/conc. HCl) X →(i. Alkaline KMnO₄; ii. Dil. HCl) Y →(conc. H₂SO₄, heat) Z. The total number of secondary H-atoms present in the final product Z is .
Answer: 4
Solution
Clemmensen reduction (Zn(Hg)/HCl) reduces the ketone C=O of acetophenone fully to CH₂, giving ethylbenzene (X). Hot alkaline KMnO₄ then oxidizes the benzylic side chain completely back to the ring, and acidification gives benzoic acid (Y). Treatment of benzoic acid with conc. H₂SO₄ and heat effects electrophilic
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account