JEE Main Chemistry question
Cyclopent-2-en-1-one →(NaBH₄, EtOH) Product. The number of H-atoms in the product formed is .
Answer: 8
Solution
NaBH₄ selectively reduces the ketone carbonyl of the enone to an allylic alcohol, leaving the ring C=C double bond intact: cyclopent-2-en-1-one (C₅H₆O)
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