(A)Aniline (then further methylated with excess )Correct
(B)Aniline (single methylation only)
(C)Nitrobenzene
(D)None of these
Answer: (A)
Solution
Aniline reacts with methyl iodide by successive -alkylations: the first equivalent gives the secondary amine -methylaniline, , and a second equivalent of methylates it further to the tertiary amine -dimethylaniline, .
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