JEE Main Chemistry question

Aniline is a weaker base than ethylamine because

(A)The lone pair of electrons on the N-atom is not freely available for coordination with a proton, due to resonance, unlike in ethylamineCorrect
(B)Its boiling point is higher than that of ethylamine
(C)It does not produce a sufficient concentration of ions in solution
(D)It is insoluble in water, while ethylamine is soluble in water

Answer: (A)

Solution

In aniline, the nitrogen lone pair is delocalised into the aromatic ring by resonance, significantly reducing its availability for accepting a proton compared to ethylamine, whose lone pair is fully

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Question ID VK-150486