JEE Main Chemistry question
CH_3I + NH_3 \rightarrow CH_3NH_2 \xrightarrow{CH_3I} (CH_3)_2NH \xrightarrow{CH_3I} (CH_3)_3N \xrightarrow{CH_3I} (CH_3)_4N^{+}I^{-}. This sequence illustrates
Answer: (A)
Solution
Successive treatment with methyl iodide methylates ammonia's nitrogen one step at a time — $ → → → →
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