JEE Main Chemistry question

The number of chiral carbons in the open-chain form of glucose is:

(A)5
(B)6
(C)3
(D)4Correct

Answer: (D)

Solution

Writing glucose in its open-chain (Fischer projection) form, CHO-CHOH-CHOH-CHOH-CHOH-CH_2OH, the four carbons bearing an group together with , a distinct chain segment on either side (C2, C3, C4

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Question ID VK-151054