JEE Main Chemistry question

Ring structure of glucose is due to hemiacetal and ring formation between:

(A) and Correct
(B) and
(C) and
(D) and

Answer: (A)

Solution

Glucose's cyclic (pyranose) form arises when the C5 hydroxyl group attacks the C1 aldehyde carbon intramolecularly, forming a six-membered hemiacetal ring (closing between C1 and C5, with

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Question ID VK-151112