JEE Main Physics question
From the top of a tower, a stone is thrown up. It reaches the ground in second. A second stone, thrown down with the same speed, reaches the ground in second. A third stone, released from rest, reaches the ground in second. Then
Answer: (B)
Solution
This is the same configuration as the free-fall/up-thrown/down-thrown relation: with h=\frac12gt_1^2-ut_1=ut_2+\frac12gt_2^2 one finds
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