JEE Main Physics question
A car, starting from rest, accelerates at the rate through a distance , then continues at constant speed for time and then decelerates at the rate to come to rest. If the total distance travelled is , then
Answer: (D)
Solution
Speed reached after the acceleration phase: . Constant-speed distance: . Deceleration distance (at , from to 0): . Total: v_1t$+2S=15S⇒
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