JEE Main Physics question
A rocket is fired upwards. Its engine explodes (stops thrusting) fully at 12 s, reaching a peak speed of 1200 ms there, after which it decelerates under gravity, its speed falling back to zero at s. The height reached by the rocket, as calculated from its velocity–time graph, is
Answer: (A)
Solution
The height equals the area under the – graph, which is a (non-isosceles) triangle of base 132 s and peak height 1200 ms (the area
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