JEE Main Physics question
From the top of a tower of height 50 m, a ball is thrown vertically upwards with a certain velocity. It hits the ground 10 s after it is thrown up. How much time does it take to cover a distance where and are two points 20 m and 40 m below the edge of the tower? (g = 10 ms)
Answer: (D)
Solution
Taking up positive from the tower edge, ms. Position: . Time to reach : $-45t-20=0⇒ -9t-4=0⇒
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