JEE Main Physics question
A body is thrown up with a velocity 100 ms. It travels 5 m in the last second of its journey (to maximum height). If the same body is thrown up with a velocity 200 ms, how much distance (in metre) will it travel in the last second (g = 10 ms)?
Answer: 5 m
Solution
The distance covered in the last second of ascent (just before ) is, by time-reversal symmetry, the same as the distance fallen in the *first* second of free fall from rest: m — independent
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