JEE Main Physics question

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m/sec. The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is (Take g = 10 m/s)

• (A)5:7
• (B)7:5Correct
• (C)3:6
• (D)6:3