JEE Main Physics question
A particle is thrown vertically upwards. If its velocity at half of the maximum height is , then maximum height attained by it is (Take )
Answer: (B)
Solution
and v^2=u^2-gh=2gh-gh=gh\Rightarrow h=v^2/g=100/10=10 m.
A particle is thrown vertically upwards. If its velocity at half of the maximum height is , then maximum height attained by it is (Take )
and v^2=u^2-gh=2gh-gh=gh\Rightarrow h=v^2/g=100/10=10 m.