JEE Main Physics question
A mass of 10 kg is suspended from a string balance. It is pulled aside by a horizontal string so that it makes an angle of 60° with the vertical. The new reading of the balance is [K CET 2008]
Answer: (A)
Solution
The vertical component of the tilted string's tension supports the weight: T cos60° = mg ⟹ T = mg/cos60° = (10×10)/0.5 = 200 N = 20 kgf.