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JEE Main Physics question

PhysicsMotion in a Straight LineJEE Main

A body of mass 4 kg is accelerated upon by a constant force, travels a distance of 5 m in the first second and a distance of 2 m in the third second. The force acting on the body is

Answer: (C)

Solution

Distance in the nth second: = u + (a/2)(2n−1). s₁ = u + a/2 = 5; s₃ = u + 5a/2

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Question ID VK-152835