JEE Main Physics question
A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N when the lift is stationary. If the lift moves downward with an acceleration of 5 ms⁻², the reading of the spring balance will be
Answer: (A)
Solution
m = 49/9.8 = 5 kg. Reading = m(g − a) = 5(9.8 − 5) = 24 N.