JEE Main Physics question
A body of mass 10 kg is acted upon by two forces, each of magnitude 10 N, making an angle of 60° with each other. Find the net acceleration of the body. [J&K CET 2007]
Answer: (B)
Solution
Resultant R = √(10² + 10² + 2·10·10·cos60°) = √(100+100+100) = 10√3 N. a = R/m = 10√3/10 = √3 ms⁻².