JEE Main Physics question
An object of mass 5 kg is attached to the hook of a spring balance and the balance is suspended vertically from the roof of a lift. The reading on the spring balance when the lift is going up with an acceleration of 0.25 ms⁻² is (take g = 10 ms⁻²) [Kerala CEE 2008]
Answer: (A)
Solution
Reading = m(g+a) = 5(10+0.25) = 51.25 N.