JEE Main Physics question
A ball falls from a 20 m height onto a floor and rebounds to 5 m. The time of contact is 0.02 s. Find the acceleration during impact. [Manipal 2008]
Answer: (D)
Solution
Speed just before impact (downward) = √(2g×20) = 20 ms⁻¹. Speed just after impact (upward) =
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