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JEE Main Physics question

PhysicsSystems of Particles and Rotational MotionJEE Main

A bullet is fired from a gun. The force on the bullet is given by F = 600 − 2×10⁵t, where F is in newton and t in second. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet?

Answer: (C)

Solution

The bullet leaves the barrel when F = 0, i.e. t = 600/(2×10⁵) = 3×10⁻³ s. Impulse =

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Question ID VK-152861