JEE Main Physics question
A gun fires a bullet each of mass 1 g with velocity 10 ms⁻¹ by exerting a constant force of 5 g-weight. Then the number of bullets fired per second is (take g = 10 ms⁻²)
Answer: (B)
Solution
F = 5 g-wt = 5×10⁻³×10 = 0.05 N. n = F/(mv) = 0.05/(0.001×10) = 5.