JEE Main Physics question
A ball of mass 0.2 kg rests on a vertical post of height 5 m. A bullet of mass 0.01 kg, travelling with a velocity v ms⁻¹ in a horizontal direction, hits the centre of the ball. After the collision, the ball and bullet travel independently. The ball hits the ground at a distance of 20 m and the bullet at a distance of 100 m from the foot of the post. The initial velocity v of the bullet is [IIT JEE 2011]
Answer: (D)
Solution
Both fly off horizontally from the same height and fall for the same time t = √(2h/g) = √(2×5/10) = 1 s. Ball's horizontal speed after collision =
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