JEE Main Physics question
A man of mass 60 kg and a boy of mass 30 kg are standing together on a frictionless ice surface. If they push each other apart, the man moves away with a speed of 0.4 ms⁻¹ relative to the ice after 5 s. They will be away from each other at a distance of
Answer: (C)
Solution
By momentum conservation, boy's speed = (60×0.4)/30 = 0.8 ms⁻¹ (opposite
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account