JEE Main Physics question
Diwali rockets are ejecting 50 g of gases per second at a velocity of 400 ms⁻¹. The accelerating force on the rocket will be
Answer: (B)
Solution
F = (dm/dt)v = 0.05×400 = 20 N.
Diwali rockets are ejecting 50 g of gases per second at a velocity of 400 ms⁻¹. The accelerating force on the rocket will be
F = (dm/dt)v = 0.05×400 = 20 N.