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JEE Main Physics question

PhysicsLaws of MotionJEE Main

A block A weighing 100 kg rests on a block B and is tied by a horizontal string to the wall at C. Block B weighs 200 kg. The coefficient of friction between A and B is 0.25 and between B and the surface is 1/3. The horizontal force P necessary to move block B should be (g = 10 ms⁻²)

Answer: (B)

Solution

Friction from A on B (A is held fixed by the string, so B slides under it) = μ_ g) = 0.25×100×10 = 250 N.

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Question ID VK-152921