JEE Main Physics question
The backside of a truck is open and a box of 40 kg is placed 5 m away from the rear end. The coefficient of friction of the box with the surface of the truck is 0.15. The truck starts from rest with 2 ms⁻² acceleration. Calculate the distance covered by the truck when the box falls off.
Answer: (A)
Solution
The box's own acceleration (driven only by friction, which cannot exceed the limiting value) is μg = 0.15×10 = 1.5 ms⁻², less than the truck's 2 ms⁻². The box's acceleration relative
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