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JEE Main Physics question

PhysicsLaws of MotionJEE Main

A block of mass 2 kg rests on a horizontal surface. If a horizontal force of 5 N is applied on the block, the frictional force on it is (μ_k = 0.4, μ_s = 0.5)

Answer: (A)

Solution

Maximum static friction = μ_s mg = 0.5×2×10 = 10 N, greater than the applied 5 N,

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Question ID VK-152926