JEE Main Physics question

PhysicsLaws of MotionJEE Main

Block A of mass 2 kg is placed over block B of mass 8 kg. The combination is placed over a rough horizontal surface. Coefficient of friction between B and the floor is 0.5. Coefficient of friction between A and B is 0.4. A horizontal force of 10 N is applied on block B. The force of friction between A and B is

Answer: (A)

Solution

Maximum friction available from the floor on the combination is μ+ = 0.5×10×10 = 50 N, which exceeds the applied

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Question ID VK-152938