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JEE Main Physics question

PhysicsLaws of MotionJEE Main

A block of mass 2 kg is at rest on a floor. The coefficient of static friction between the block and the floor is 0.54. A horizontal force of 2.8 N is applied to the block. What should be the frictional force between the block and the floor? (Take g = 10 m/s²)

Answer: (C)

Solution

Maximum static friction = 0.54×2×10 = 10.8 N, greater than the applied 2.8 N,

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Question ID VK-152941