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JEE Main Physics question

PhysicsLaws of MotionJEE Main

A block of weight 5 N is pushed against a vertical wall by a force of 12 N. The coefficient of friction between the wall and the block is 0.6. The magnitude of the force exerted by the wall on the block is

Answer: (D)

Solution

Normal reaction N = 12 N (from the push). Maximum available friction = μN = 0.6×12 = 7.2 N, more than

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Question ID VK-152984