JEE Main Physics question

PhysicsLaws of MotionJEE Main

Block A of mass 2 kg is placed over a block B of mass 8 kg. The combination is placed on a rough horizontal surface. If g = 10 ms⁻², the coefficient of friction between B and the floor is 0.5, the coefficient of friction between A and B is 0.4, and a horizontal force of 10 N is applied on the 8 kg block, then the force of friction between A and B is

Answer: (D)

Solution

Maximum friction available from the floor on the combination = μ+ = 0.5×10×10 = 50 N, far exceeding the applied 10 N; the whole system

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Question ID VK-152986