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JEE Main Physics question

PhysicsSystems of Particles and Rotational MotionJEE Main

A ball of mass 0.2 kg is thrown normally against a wall with a speed of 1.75 ms⁻¹ and rebounds elastically. The impulse of the force by the ball on the wall is

Answer: (B)

Solution

On an elastic, normal rebound, Δp = m(v−(−v)) = 2mv = 2×0.2×1.75 = 0.7 N·s.

Question ID VK-152987