JEE Main Physics question

Physics Laws of Motion JEE Main

A machine gun fires n bullets per second, each of mass m, with velocity u. The force of recoil is

(A)mng
(B)mnuCorrect
(C)mnug
(D)mnu/g

Answer: (B)

Solution

Force = rate of change of momentum = n·m·u.

Question ID VK-152994