JEE Main Physics question

PhysicsLaws of MotionJEE Main

A block is gently placed on a conveyor belt moving horizontally with constant speed. After 4 s, the velocity of the block becomes equal to the velocity of the belt. If the coefficient of friction between the block and the belt is 0.2, then the velocity of the conveyor belt is (g = 10 ms⁻²)

Answer: (D)

Solution

Friction accelerates the block at a = μg = 2 ms⁻² until it matches the belt. v = at = 2×4 = 8 ms⁻¹.

Question ID VK-153012