JEE Main Physics question
A block is gently placed on a conveyor belt moving horizontally with constant speed. After 4 s, the velocity of the block becomes equal to the velocity of the belt. If the coefficient of friction between the block and the belt is 0.2, then the velocity of the conveyor belt is (g = 10 ms⁻²)
Answer: (D)
Solution
Friction accelerates the block at a = μg = 2 ms⁻² until it matches the belt. v = at = 2×4 = 8 ms⁻¹.