JEE Main Physics question

PhysicsLaws of MotionJEE Main

A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. Force P is applied at one end of the rope. The force which the rope exerts on the block is

Answer: (D)

Solution

System acceleration a = P/(M+m). Force transmitted to the block = Ma = PM/(M+m).

Question ID VK-153020